Question

multiple - choice question
we will use the equation: ( w = f\times d ).
f: force and d: distance/displacement.
lets say the amount of applied force each weightlifter exerted was 300 n. what would the amount of work be? use this equation ( w = 300 ) (force) ( \times 2 ) (distance)
30,000 joules
600 joules
rewatch

Explanation:

Step1: Substitute values into formula

Given \( W = F\times d\), \(F = 300\space N\), \(d=2\space m\).
So \(W=300\times2\).

Step2: Calculate the product

\(300\times2 = 600\).

Answer:

600 Joules