Question

math focus

1. identify when the voltage

doubles, what happens to
the current?

Explanation:

Step1: Recall Ohm's Law

Ohm's Law is \(V = IR\), where \(V\) is voltage, \(I\) is current, and \(R\) is resistance. Assuming resistance \(R\) is constant (since no information about \(R\) changing is given).

Step2: Analyze the effect of doubling voltage

If \(V\) doubles, let the new voltage \(V_{new}=2V\). From \(V = IR\), we have \(I=\frac{V}{R}\). For the new situation, \(I_{new}=\frac{V_{new}}{R}\). Substituting \(V_{new} = 2V\) into the formula, we get \(I_{new}=\frac{2V}{R}\). Since \(I=\frac{V}{R}\), then \(I_{new} = 2I\).

Answer:

The current also doubles.