Question

a light bulb has a resistance of 5 ohms and a maximum current of 10 a. how much voltage can be applied before the bulb will break?

Explanation:

Step1: Recall Ohm's Law

Ohm's Law is given by the formula \(V = IR\), where \(V\) is voltage, \(I\) is current, and \(R\) is resistance.

Step2: Substitute the given values

We are given that \(R = 5\ \Omega\) and \(I=10\ A\). Substituting these into the formula \(V = IR\), we get \(V=(10\ A)\times(5\ \Omega)\).

Step3: Calculate the voltage

\(V = 10\times5=50\ V\).

Answer:

\(50\ V\)