Question

a light bulb has a resistance of 360 ω. what is the current in the bulb when it has a potential difference of 120 v across it? 0.33 a 3 a 480 a 43,200 a

Explanation:

Step1: Recall Ohm's Law

Ohm's Law is $I = \frac{V}{R}$, where $I$ is current, $V$ is voltage, and $R$ is resistance.

Step2: Substitute values into formula

Given $V = 120\ \text{V}$ and $R = 360\ \Omega$, calculate $I = \frac{120}{360}$.

Step3: Simplify the result

$\frac{120}{360} = \frac{1}{3} \approx 0.33\ \text{A}$.

Answer:

0.33 A