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Question
in lacrosse, a ball is thrown from a net on the end of a stick by rotating the stick and forearm about the elbow. if the angular velocity of the ball about the elbow joint is 25.0 rad/s and the ball is 1.15 m from the elbow joint, what is the velocity of the ball?
m/s
resources
reading
Step1: Recall the formula for linear velocity
The formula relating linear velocity \(v\), angular velocity \(\omega\), and radius \(r\) is \(v = r\omega\).
Step2: Substitute the given values
Given \(\omega=25.0\space rad/s\) and \(r = 1.15\space m\).
Substitute into the formula: \(v=(1.15\space m)\times(25.0\space rad/s)\)
$$v = 1.15\times25$$
$$v=28.75$$
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\(28.75\)