Question

kyle has a mass of 54 kg and is jogging at a velocity of 3 m/s. what is kyle’s kinetic energy? (formula: $ke = \frac{1}{2}mv^{2}$)
18 j
81 j
162 j
243 j

Explanation:

Step1: Substitute values into formula

Given \(m = 54\space kg\) and \(v=3\space m/s\), substitute into \(KE=\frac{1}{2}mv^{2}\).
\(KE=\frac{1}{2}\times54\times(3)^{2}\)

Step2: Calculate \(3^{2}\)

\(3^{2}=9\), so the formula becomes \(KE = \frac{1}{2}\times54\times9\)

Step3: Calculate \(\frac{1}{2}\times54\)

\(\frac{1}{2}\times54 = 27\), then \(KE=27\times9\)

Step4: Multiply 27 and 9

\(27\times9 = 243\)

Answer:

243 J