Question

**kinetic energy problems
formula: ke = ½ mv²

1. what is the kinetic energy of a jogger with a mass of 65.0 kg traveling at a speed of 2.5 m/s?

Explanation:

Step1: Substitute values into formula

Given \(m = 65.0\space kg\), \(v=2.5\space m/s\), \(KE=\frac{1}{2}mv^{2}\).
So \(KE=\frac{1}{2}\times65.0\times(2.5)^{2}\).

Step2: Calculate \((2.5)^{2}\)

\((2.5)^{2}=2.5\times2.5 = 6.25\).
Then \(KE=\frac{1}{2}\times65.0\times6.25\).

Step3: Calculate \(\frac{1}{2}\times65.0\)

\(\frac{1}{2}\times65.0 = 32.5\).
Now \(KE=32.5\times6.25\).

Step4: Final multiplication

\(32.5\times6.25=203.125\space J\).

Answer:

\(203.125\space J\)