Question

7/8 kg of a substance occupies a volume of 5/6 cubic meters. what is the density of the substance in kg per cubic meter? answer

Explanation:

Step1: Recall the formula for density

Density $
ho=\frac{m}{V}$, where $m$ is mass and $V$ is volume. Here, $m = \frac{7}{8}\text{ kg}$ and $V=\frac{5}{6}\text{ m}^3$.

Step2: Substitute the values into the formula

$
ho=\frac{\frac{7}{8}}{\frac{5}{6}}$.

Step3: Divide the fractions

Dividing by a fraction is equivalent to multiplying by its reciprocal. So, $
ho=\frac{7}{8}\times\frac{6}{5}$.
Multiply the numerators ($7\times6 = 42$) and the denominators ($8\times5=40$). Then $
ho=\frac{42}{40}$.

Step4: Simplify the fraction

$\frac{42}{40}=\frac{21}{20}=1.05$.

Answer:

The density of the substance is $\frac{21}{20}\text{ kg/m}^3$ or $1.05\text{ kg/m}^3$.