Question

1. a 3.0 kg model airplane is traveling at a speed of 33 m/s. the operator then increases the speed up to 45 m/s in 2.0 seconds. how much force did the engine need in order to make this change?

Explanation:

Step1: Calculate the acceleration

We use the formula \(a=\frac{v - u}{t}\), where \(u = 33\ m/s\), \(v=45\ m/s\), \(t = 2.0\ s\).

$$a=\frac{45 - 33}{2}=\frac{12}{2}=6\ m/s^{2}$$

Step2: Calculate the force

We use Newton's second law \(F = ma\), where \(m = 3.0\ kg\), \(a=6\ m/s^{2}\)

$$F=3\times6 = 18\ N$$

Answer:

\(18\ N\)