Question

item 12 (12 points) in the table below, fill in the network portion, first available host, last available host, and broadcast addresses for the subnet. the network portion is red and the host portion blue. these rules of matching the first three octets (network octets) and making unique fourth octets apply for all class c subnets (first octet 192 to 223). the first one has been completed for you.

subnet class c

subnet	network portion (3 octets only)	first available host (last octet only)	last available host (last octet only)	broadcast (last octet only)
192.168.130.0
200.123.250.0
223.9.7.0

Explanation:

Step1: Identify network portion

For Class C subnets, first 3 octets are network portion.

Step2: Determine first available host

First available host in last octet is 1.

Step3: Determine last available host

Last available host in last octet is 254 for Class C.

Step4: Determine broadcast address

Broadcast address in last octet is 255 for Class C.

Answer:

Subnet	Network Portion (3 octets only)	First available host (last octet only)	Last available host (last octet only)	Broadcast (last octet only)
200.123.250.0	200.123.250	.1	.254	.255
223.9.7.0	223.9.7	.1	.254	.255