Question

indicator measurement: the indicator shown has been mastered using a part that measures 2.500 inches in length. what is the actual length of the part shown?

Explanation:

Step1: Determine the graduation value

The dial has 100 divisions in one full rotation. The total measurement range for the dial (assuming it's a 0 - 100 scale for measurement deviation) and if we assume each division is \(0.001\) inches (a common graduation for such indicators).

Step2: Calculate the deviation

The indicator hand is at 75. So the deviation from the master part is \(75\times0.001 = 0.075\) inches.

Step3: Calculate the actual length

The master part is \(2.500\) inches. Since the indicator is measuring (assuming the scale is such that higher values mean the part is shorter - common in some indicator setups). The actual length \(L=2.500 - 0.075\)

$$L = 2.500-0.075=2.425$$

Answer:

\(2.425\) inches