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Identify the given data
Using the Electrical Devices knowledge point, we analyze the table containing energy data for four types of light bulbs during one minute of use:
- Incandescent: Useful energy output (light) = \(180\text{ J}\), Total energy input = \(3\,600\text{ J}\)
- Fluorescent: Useful energy output (light) = \(250\text{ J}\), Total energy input = \(2\,400\text{ J}\)
- Halogen: Useful energy output (light) = \(450\text{ J}\), Total energy input = \(3\,000\text{ J}\)
- LED: Useful energy output (light) = \(660\text{ J}\), Total energy input = \(1\,300\text{ J}\)
Calculate efficiency for each bulb
Using the Energy Transformation knowledge point, efficiency is calculated as:
$$\text{Efficiency} = \frac{\text{Useful Energy Output}}{\text{Total Energy Input}} \times 100\%$$
- Incandescent:
$$\text{Efficiency} = \frac{180}{3\,600} \times 100\% = 5\%$$
- Fluorescent:
$$\text{Efficiency} = \frac{250}{2\,400} \times 100\% \approx 10.4\%$$
- Halogen:
$$\text{Efficiency} = \frac{450}{3\,000} \times 100\% = 15\%$$
- LED:
$$\text{Efficiency} = \frac{660}{1\,300} \times 100\% \approx 50.8\%$$
Determine the most efficient bulb
Comparing the calculated efficiency values:
- Incandescent: \(5\%\)
- Fluorescent: \(10.4\%\)
- Halogen: \(15\%\)
- LED: \(50.8\%\)
The LED bulb has the highest efficiency.
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