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how much kinetic energy (joules) did a basketball with a mass of 625 ki…

Question

how much kinetic energy (joules) did a basketball with a mass of 625 kilograms hit with a velocity of 35 m/s create? (round your answers) formula is: ke = ½ m v² kinetic energy mass velocity

Explanation:

Step1: Sustituir valores en la fórmula

Dado que \( KE=\frac{1}{2}mv^{2} \), \( m = 6.25\ kg \) y \( v = 35\ m/s \).

Step2: Calcular \( v^{2} \)

\( v^{2}=35^{2}=1225 \)

Step3: Calcular \( \frac{1}{2}mv^{2} \)

\( KE=\frac{1}{2}\times6.25\times1225=\frac{6.25\times1225}{2}=\frac{7656.25}{2}=3828.125\approx383 \)

Answer:

C. 383