Question

1.) how much heat is needed to raise the temperature of 200g of water by 95°c? the specific heat of water is 4.18j/g°c.

Explanation:

Step1: Recall the heat formula

The formula for heat \(Q = mc\Delta T\), where \(m\) is mass, \(c\) is specific heat, \(\Delta T\) is temperature change.

Step2: Substitute the values

Given \(m = 200g\), \(c=4.18J/g^{\circ}C\), \(\Delta T = 95^{\circ}C\).
\(Q=(200g)\times(4.18J/g^{\circ}C)\times(95^{\circ}C)\)

Step3: Calculate the result

\(Q = 200\times4.18\times95\)
\(Q=200\times397.1\)
\(Q = 79420J\)

Answer:

\(79420J\)