Question

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an object has an acceleration of 6.0 m/s/s. if the net force acting upon this object were halved (i.e., one - half of the original net force), then its new acceleration would be ______ m/s/s.
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new acceleration (in m/s/s)
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Explanation:

Step1: Apply Newton's second law

Newton's second law is \(F = ma\). Let the original force be \(F_1\), mass be \(m\), and original acceleration \(a_1=6.0\ m/s^2\), so \(F_1 = ma_1\).

Step2: Analyze the new - force situation

The new force \(F_2=\frac{1}{2}F_1\). Substitute \(F_1 = ma_1\) into \(F_2\), we get \(F_2=\frac{1}{2}ma_1\). Since \(F_2 = ma_2\) (Newton's second law for the new situation), then \(ma_2=\frac{1}{2}ma_1\).

Step3: Solve for the new acceleration

Cancel out \(m\) (mass remains constant) from both sides of the equation \(ma_2=\frac{1}{2}ma_1\). We get \(a_2=\frac{1}{2}a_1\). Substitute \(a_1 = 6.0\ m/s^2\) into the formula, \(a_2=\frac{1}{2}\times6.0\ m/s^2\).

Answer:

\(3.0\)