Question

gravitational force calculation problems
formula: $f_g=\frac{gm_1m_2}{r^2}$, $g = 6.674 \times 10^{-11} \frac{n\cdot m^2}{kg^2}$

1. calculate the gravitational force between a person of mass 80 kg and another person of mass 70 kg standing 1.5m apart.

Explanation:

Step1: Substitute values into formula

$$F_G=\frac{Gm_1m_2}{r^2}=\frac{6.674\times10^{-11}\times80\times70}{1.5^2}$$

Step2: Calculate numerator

$6.674\times10^{-11}\times80\times70 = 6.674\times10^{-11}\times5600=3.73744\times10^{-7}$

Step3: Calculate denominator

$1.5^2 = 2.25$

Step4: Calculate final result

$$F_G=\frac{3.73744\times10^{-7}}{2.25}\approx1.66\times10^{-7}\text{ N}$$

Answer:

The gravitational force is approximately $1.66\times10^{-7}\text{ N}$.