Question

the given equation relates the resistance r, in ohms, of a wire to its length l, in meters, and its cross - sectional area a, in square meters. which equation correctly expresses the length, in meters, of the wire in terms of its resistance, in ohms, and its cross - sectional area, in square meters? r = 0.43l/a a. l = r - a/0.43 b. l = r + a/0.43 c. l = 0.43r/a d. l = ar/0.43

Explanation:

Step1: Isolate \(l\) in the equation \(R = \frac{0.43l}{A}\).

Multiply both sides by \(A\): \(RA=0.43l\).

Step2: Solve for \(l\).

Divide both sides by \(0.43\): \(l=\frac{RA}{0.43}\).

Answer:

C. \(l = \frac{0.43R}{A}\)