Question

four forces act concurrently on a block on a horizontal surface as shown in the diagram below. as a result of these forces, the block (1) moves at constant speed to the right (2) moves at constant speed to the left (3) accelerates to the right (4) accelerates to the left 40. a 4.0 - kilogram object is accelerated at 3.0 meters per second² north by an unbalanced force. the same unbalanced force acting on a 2.0 - kilogram object will accelerate this object toward the north at (1) 12 m/s² (2) 6.0 m/s² (3) 3.0 m/s² (4) 1.5 m/s² june 2012 5. which object has the greatest inertia? (1) a 15 - kg mass traveling at 5.0 m/s (2) a 10 - kg mass traveling at 10 m/s (3) a 10 - kg mass traveling at 5.0 m/s (4) a 5.0 - kg mass traveling at 15 m/s 7.

Explanation:

Step1: Calculate the unbalanced force for the first object

According to Newton's second law \(F = ma\). Given \(m_1=4.0\space kg\) and \(a_1 = 3.0\space m/s^{2}\), then \(F=m_1a_1\).

$$F=(4.0\space kg)\times(3.0\space m/s^{2}) = 12\space N$$

Step2: Calculate the acceleration of the second object

Since the force \(F = 12\space N\) is the same for the second object with \(m_2 = 2.0\space kg\). Using \(a=\frac{F}{m}\), we substitute \(F = 12\space N\) and \(m_2=2.0\space kg\) into the formula.

$$a_2=\frac{12\space N}{2.0\space kg}=6.0\space m/s^{2}$$

Answer:

(2) \(6.0\space m/s^{2}\)