QUESTION IMAGE
Question
forces that change motion quick check
during a game of pool, a cue ball travels to the left with 70 n of force and collides with the four ball moving with a force of 50 right. if you assign a negative value to the force moving to the right, what is the net force of this system? (1 point)
20 m/s2
-20 n
120 n
20 n
Step1: Define forces
Let the force to the left be positive. So, \(F_1 = 70N\) (cue - ball force to the left), and \(F_2=- 50N\) (four - ball force to the right, since negative is assigned to right - moving force).
Step2: Calculate net force
The net force \(F_{net}=F_1 + F_2\). Substitute the values: \(F_{net}=70+( - 50)\). Using the rule \(a+( - b)=a - b\), we get \(F_{net}=70 - 50\).
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\(20N\)