Question

the force factor refers to the amount an initial force value is multiplied by to get a new value. determine the force factor for each row in the table by calculating how many times bigger |f_a| is compared to the initial value, rounded to the nearest whole number. enter your answers in the boxes.

m_a (kg)	m_b (kg)		f_a	(n)	force factor
10.0·10⁵	20.0·10⁵	0.0834	\square
20.0·10⁵	20.0·10⁵	0.1667	\square
10.0·10⁵	30.0·10⁵	0.2501	\square

Explanation:

Step1: Calculate force factor for second row

The initial force value (from first row) is \( 0.0417 \, \text{N} \). For the second row, \( |F_A| = 0.0834 \, \text{N} \). The force factor is \( \frac{0.0834}{0.0417} \).
\( \frac{0.0834}{0.0417} = 2 \)

Step2: Calculate force factor for third row

For the third row, \( |F_A| = 0.1667 \, \text{N} \). The force factor is \( \frac{0.1667}{0.0417} \approx 4 \) (rounded to nearest whole number).

Step3: Calculate force factor for fourth row

For the fourth row, \( |F_A| = 0.2501 \, \text{N} \). The force factor is \( \frac{0.2501}{0.0417} \approx 6 \) (rounded to nearest whole number).

Answer:

Second row: 2
Third row: 4
Fourth row: 6