find the force a 68.5 kg person would experience while standing on the surface of mars. mars has a mass of 6.43 x 10^{23} kg and a radius of 3.43 x 10^{6}m from its center to the surface.
259 n
790 n
8.57 x 10^{8} n
250 n

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Accepted Answer

# Explanation:
## Step1: Escribir la fórmula de la ley de gravitación universal
La ley de gravitación universal de Newton es $ F = G\frac{Mm}{r^{2}} $, donde $ G = 6.67\times10^{- 11}\space N\cdot m^{2}/kg^{2} $, $ M = 6.43\times10^{23}\space kg $, $ m = 68.5\space kg $, $ r = 3.43\times10^{6}\space m $.
## Step2: Sustituir los valores en la fórmula
Sustituir los valores en la fórmula:
$$
\begin{align*}
F&=(6.67\times 10^{-11})\frac{(6.43\times 10^{23})(68.5)}{(3.43\times 10^{6})^{2}}\
&=(6.67\times 10^{-11})\frac{4.39455\times 10^{25}}{1.17649\times 10^{13}}\
&=(6.67\times 10^{-11})\times3.735\times 10^{12}\
&= 250\space N
\end{align*}
$$

# Answer:
250 N

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Question

Explanation:

Step1: Escribir la fórmula de la ley de gravitación universal

Step2: Sustituir los valores en la fórmula

Answer: