Question

fill in the name and empirical formula of each ionic compound that could be formed from the ions in this table.
some ionic compounds
cation \tanion \tempirical formula \tname of compound
na⁺ \tbr⁻ \t□ \t□
na⁺ \tf⁻ \t□ \t□
na⁺ \tcl⁻ \t□ \t□
na⁺ \ti⁻ \t□ \t□

Explanation:

Step1: For \( \text{Na}^+ \) and \( \text{Br}^- \)

To form an ionic compound, the charges must balance. \( \text{Na}^+ \) has a +1 charge and \( \text{Br}^- \) has a -1 charge. So the empirical formula is \( \text{NaBr} \) (since \( 1\times(+1) + 1\times(-1) = 0 \)). The name of the compound is Sodium Bromide (using the cation name first, then the anion name with -ide suffix).

Step2: For \( \text{Na}^+ \) and \( \text{F}^- \)

\( \text{Na}^+ \) (+1) and \( \text{F}^- \) (-1). The empirical formula is \( \text{NaF} \) (charge balance: \( +1 + (-1) = 0 \)). The name is Sodium Fluoride.

Step3: For \( \text{Na}^+ \) and \( \text{Cl}^- \)

\( \text{Na}^+ \) (+1) and \( \text{Cl}^- \) (-1). Empirical formula is \( \text{NaCl} \) (charge balance holds). Name is Sodium Chloride.

Step4: For \( \text{Na}^+ \) and \( \text{I}^- \)

\( \text{Na}^+ \) (+1) and \( \text{I}^- \) (-1). Empirical formula is \( \text{NaI} \) (charge balance: \( +1 + (-1) = 0 \)). Name is Sodium Iodide.

cation	anion	empirical formula	name of compound
\( \text{Na}^+ \)	\( \text{F}^- \)	\( \text{NaF} \)	Sodium Fluoride
\( \text{Na}^+ \)	\( \text{Cl}^- \)	\( \text{NaCl} \)	Sodium Chloride
\( \text{Na}^+ \)	\( \text{I}^- \)	\( \text{NaI} \)	Sodium Iodide

Answer:

The completed table is as shown above with empirical formulas \( \text{NaBr} \), \( \text{NaF} \), \( \text{NaCl} \), \( \text{NaI} \) and compound names Sodium Bromide, Sodium Fluoride, Sodium Chloride, Sodium Iodide respectively.