fill in the blank question
a photon has a frequency of 1.0×10^{15}s^{-1}, and plancks constant is 6.6×10^{-34} j·s. the energy of the photon equals ×10^{-19} j.

Question

Accepted Answer

# Explanation:
## Step1: Use the formula for photon energy
The formula for the energy of a photon is $E = h
u$, where $h$ is Planck's constant and $
u$ is the frequency.
## Step2: Substitute the given values
Given $h = 6.6\times10^{-34}\text{ Js}$ and $
u=1.0\times 10^{15}\text{ s}^{-1}$.
$$
\begin{align*}
E&=(6.6\times 10^{-34}\text{ Js})\times(1.0\times 10^{15}\text{ s}^{-1})\
&=6.6\times10^{-34 + 15}\text{ J}\
&=6.6\times10^{-19}\text{ J}
\end{align*}
$$

# Answer:
$6.6$

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QUESTION IMAGE

Question

Explanation:

Step1: Use the formula for photon energy

Step2: Substitute the given values

Answer: