Question

evaluate known quantities in the conservation equations. (cont.)
before the collision, puck 1 travels in the +y - direction with a speed of 1.05 m/s so that ( v_{y1}=+1.05 ) m/s.
what is the value of ( v_{x1} )?
incorrect. after the collision, the two pucks travel together with a speed of 1.85 m/s in a direction ( 28.0^{circ} ) above the negative x - axis. m/s

additional problems
question 6.2a:
two blocks slide on a collision course across a frictionless surface,
of ( v_{1}=8.95 ) m/s. the second block has mass ( m = 7.40\times10^{-2} ) kg
collision, the second block is observed sliding at ( v_{f}=4.95 ) m/s in a

puck1: ( m = 1.90\times10^{-2} )
( v_{i}=1.05 ) m/s
puck 2: ( m = 1.90\times10^{-2} )
( v_{f}=1.85 ) m/s

Explanation:

Step1: Analyze the x - direction motion before collision

Before the collision, Puck 1 travels in the + y - direction. So, its velocity in the x - direction \(v_{1x}=0\ m/s\) (because there is no component of its initial velocity in the x - direction).

Answer:

\(0\ m/s\)