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the energy efficiency of electric vehicles is usually rated in terms of…

Question

the energy efficiency of electric vehicles is usually rated in terms of the kilowatt hours (of energy) required to drive 100 miles, or kwh/100 mi. an electric car is rated at 24 kwh/100 mi

a. how much energy (in kilowatt hours) is required to drive this electric car 150 miles?
b. assuming electricity costs $0.12/kwh, how much does it cost to drive this electric car 60 miles?
c. if you drive 12,000 miles in a year, what is the cost of a year’s worth of travel in this electric car?
d. if you drove a gas - powered car with mileage of 31 mpgal and paid $2.40/gal, how much would it cost to drive 12,000 miles?

a. driving 150 miles requires 36 kwh of energy

b. it costs $0.864? to drive 60 miles
(found to the nearest cent as needed.)

Explanation:

Part a

Step1: Understand the rate

The car is rated at \(24\) kWh/100 mi, meaning for every 100 miles, it uses 24 kWh.

Step2: Set up the proportion

Let \(x\) be the energy for 150 miles. We have \(\frac{24\ \text{kWh}}{100\ \text{mi}}=\frac{x}{150\ \text{mi}}\).

Step3: Solve for \(x\)

Cross - multiply: \(100x = 24\times150\). Then \(x=\frac{24\times150}{100}=24\times1.5 = 36\) kWh.

Step1: Find energy for 60 miles

First, use the rate \(\frac{24\ \text{kWh}}{100\ \text{mi}}\). Let \(y\) be the energy for 60 miles. \(\frac{24}{100}=\frac{y}{60}\), so \(y=\frac{24\times60}{100}=14.4\) kWh.

Step2: Calculate cost

Electricity costs \(\$0.12\) per kWh. Cost \(=14.4\times0.12=\$1.728\approx\$1.73\) (rounded to the nearest cent).

Step1: Find energy for 12000 miles

Using the rate \(\frac{24\ \text{kWh}}{100\ \text{mi}}\), let \(z\) be the energy for 12000 miles. \(\frac{24}{100}=\frac{z}{12000}\), so \(z=\frac{24\times12000}{100}=24\times120 = 2880\) kWh.

Step2: Calculate cost

Cost \(=2880\times0.12=\$345.60\).

Answer:

36 kWh

Part b