Question

energy calculations
the planck equation:
e = energy of photons (in joules)
e = hv
v = frequency (hz)
h = 6.626 x 10^-34 (plancks constant)
instructions: use the planck equation to answer the questions below:

1. calculate the energy of medical x - rays with a frequency of 5.25 x 10^10 hz.

energy=(6.63 x 10^-34)(5.2 x 10^10 hz)=
energy = 3.5 x 10^-23 j

1. calculate the frequency of large waves that have an energy of 4.42 x 10^-22 j.
2. what is the frequency of waves that have an energy of 8.18 x 10^-20 j?
3. what is the energy of infrared rays with a frequency of 3.20 x 10^12 hz.

Explanation:

Step1: Recall Planck's equation

$E = h
u$, where $E$ is energy, $h = 6.626\times10^{-34}\ J\cdot s$ is Planck's constant and $
u$ is frequency.

Step2: Solve question 2

Given $E = 4.42\times 10^{-22}\ J$, we need to find $
u$. Rearranging Planck's equation gives $
u=\frac{E}{h}$.
Substitute the values: $
u=\frac{4.42\times 10^{-22}\ J}{6.626\times 10^{-34}\ J\cdot s}\approx6.67\times 10^{11}\ Hz$.

Step3: Solve question 3

Given $E = 8.18\times 10^{-20}\ J$. Using $
u=\frac{E}{h}$, substitute the values: $
u=\frac{8.18\times 10^{-20}\ J}{6.626\times 10^{-34}\ J\cdot s}\approx1.24\times 10^{14}\ Hz$.

Step4: Solve question 4

Given $
u = 3.20\times 10^{12}\ Hz$. Using $E = h
u$, substitute the values: $E=(6.626\times 10^{-34}\ J\cdot s)\times(3.20\times 10^{12}\ Hz)= 2.12\times 10^{-21}\ J$.

Answer:

1. $\approx6.67\times 10^{11}\ Hz$
2. $\approx1.24\times 10^{14}\ Hz$
3. $2.12\times 10^{-21}\ J$