Question

during a physics lab, dangelo weighs an object with an actual weight of 14.8 grams. however, his scale is miscalibrated and reads 17.2 as the object’s weight. what is the percent of error in the scale’s reading, to the nearest hundredth? %

Explanation:

Step1: Find the absolute error

The absolute error is the absolute difference between the measured value and the actual value. So, \( |17.2 - 14.8| = 2.4 \).

Step2: Calculate percent error

The formula for percent error is \( \text{Percent Error} = \frac{|\text{Measured Value} - \text{Actual Value}|}{\text{Actual Value}} \times 100\% \). Substituting the values, we get \( \frac{2.4}{14.8} \times 100\% \).

Step3: Compute the value

First, calculate \( \frac{2.4}{14.8} \approx 0.16216 \). Then multiply by 100% to get \( 0.16216 \times 100\% = 16.216\% \), which rounds to 16.22% when rounded to the nearest hundredth.

Answer:

16.22%