Question

as the distance between two charged objects increases, the strength of the electrical force between the objects varies. remains the same. increases. decreases.

Explanation:

According to Coulomb's law \( F = k\frac{q_1q_2}{r^2}\), where \(F\) is the electrical force, \(k\) is a constant, \(q_1\) and \(q_2\) are the charges of the two objects, and \(r\) is the distance between them. When the distance \(r\) increases, the value of \(F\) (the electrical force) decreases because \(F\) is inversely proportional to the square of \(r\).

Answer:

decreases.