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determine the number of significant figures in each of the following nu…

Question

determine the number of significant figures in each of the following numbers:
1.2500
choose
choose
0.0025
3
5
1
4
2
0.00250
62000.
560
choose

Explanation:

Step1: Determine significant figures for 1.2500

Non - zero digits (1, 2, 5) are significant. Trailing zeros in a decimal number are significant. So, 1.2500 has 5 significant figures.

Step2: Determine significant figures for 0.0025

Leading zeros (before non - zero digits) are not significant. Non - zero digits (2, 5) are significant. So, 0.0025 has 2 significant figures.

Step3: Determine significant figures for 0.00250

Leading zeros are not significant. Non - zero digits (2, 5) and the trailing zero (after non - zero digit in decimal) are significant. So, 0.00250 has 3 significant figures.

Step4: Determine significant figures for 62000.

The decimal at the end makes it clear. Non - zero digits (6, 2) and the trailing zeros (since it's a decimal - indicated number) are significant. So, 62000. has 5 significant figures. But if it was 62000 (no decimal), it's ambiguous. Here with the decimal, 62000. has 5. Wait, no! Wait, 62000. is 6.2000×10⁴. Non - zero digits (6, 2) and trailing zeros in decimal. So 5? No, wait 62000. The digits 6,2 and the three zeros (since it's a decimal - marked number). Wait no: rules: all digits from the first non - zero digit (6) to the last digit (0) are significant. So 62000. has 5. But wait, another approach: 62000. = 6.2000×10⁴. So 5 significant figures.

Step5: Determine significant figures for 560

Trailing zero in a non - decimal number. If it's 560, it can be 5.6×10² (2 significant figures) or 5.60×10² (3). But usually, if no decimal, trailing zero may not be. But if written as 560 (no decimal), ambiguous. But if we assume standard, 560 has 2 (5 and 6, zero is not). But if it's 560. (with decimal), it's 3. Assuming no decimal as in the problem (560), 2.

Answer:

1.2500: 5, 0.0025: 2, 0.00250: 3, 62000.: 5, 560: 2