Question

1. density calculation: if we know that 10.0 cm3 of ice has a mass of 9.17 g, what is the density of the ice? (2 points)

show work below:
density of the ice:

1. density calculation: what is the density of a 15 g box measuring 10 cm by 5 cm by 2 cm? (2 points)

show work below:
density of the box:

Explanation:

Step1: Recall the density formula

The formula for density is \(
ho=\frac{m}{V} \), where \(
ho \) is density, \( m \) is mass, and \( V \) is volume.

Step2: Solve for the density of ice

Given \( m = 9.17\ g \) and \( V=10.0\ cm^{3} \).
Substitute into the formula: \(
ho=\frac{9.17\ g}{10.0\ cm^{3}} = 0.917\ g/cm^{3} \).

Step3: Calculate the volume of the box

The volume of a rectangular box is \( V = l\times w\times h \).
Given \( l = 10\ cm \), \( w = 5\ cm \), \( h = 2\ cm \).
\( V=10\times5\times2=100\ cm^{3} \).

Step4: Solve for the density of the box

Given \( m = 15\ g \) and \( V = 100\ cm^{3} \).
Substitute into the formula: \(
ho=\frac{15\ g}{100\ cm^{3}}=0.15\ g/cm^{3} \).

Answer:

Density of the ice: \( 0.917\ g/cm^{3} \)
Density of the box: \( 0.15\ g/cm^{3} \)