Question

a cylinder has a base radius of 2 feet and a height of 5 feet. what is its volume in cubic feet, to the nearest tenths place?
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answer attempt 1 out of 2
v =

Explanation:

Step1: Recall the formula for the volume of a cylinder

The formula for the volume \( V \) of a cylinder is \( V=\pi r^{2}h \), where \( r \) is the radius of the base and \( h \) is the height of the cylinder.

Step2: Substitute the given values into the formula

We are given that \( r = 2 \) feet and \( h=5 \) feet. Substituting these values into the formula, we get \( V=\pi\times(2)^{2}\times5 \).

Step3: Simplify the expression

First, calculate \( (2)^{2}=4 \). Then, multiply \( 4\times5 = 20 \). So the volume is \( V = 20\pi \).

Step4: Approximate the value to the nearest tenths place

We know that \( \pi\approx3.14159 \), so \( 20\pi\approx20\times3.14159 = 62.8318 \). Rounding this to the nearest tenths place, we look at the hundredths digit which is 3. Since \( 3<5 \), we round down. So \( 62.8318\approx62.8 \).

Answer:

\( 62.8 \)