Question

consider the following series of arithmetic expressions.
int a = -2;
int b = 5;
int c = 8;
system.out.println(b + 3 * b % 11);
c += 3 b + -1 a;
system.out.println(c);
what is the output produced by this code?
925
825
977

Explanation:

Step1: Calculate the first print statement

According to the order of operations (multiplication and modulus before addition), for b + 3 * b % 11 where b = 5:
First, calculate 3 b = 35 = 15, then 15 % 11=4 (since \(15 = 1\times11 + 4\)), and then b+4 = 5 + 4=9.

Step2: Calculate the value of c

The original value of c is 8. The expression c += 3 b+-1 a is equivalent to c=c+(3 * b - a). Substitute a=-2 and b = 5:
First, calculate 3b - a=35-(-2)=15 + 2=17. Then c=8 + 17=25.

Answer:

925