Question

consider the following incomplete method. method findnext is intended to return the index of the first occurrence of the value val beyond the position star in array arr. // returns arr.length if val is not found after position start; public int findnext(int arr, int val, int start) { int pos = start + 1; while ( / condition / ) { pos++; } return pos; } for example, consider the following code segment. int arr = {11, 22, 100, 33, 100, 11, 44, 100}; system.out.println(findnext(arr, 100, 2)); the execution of the code segment should result in the value 4 being printed. which of the following expressions could be used to replace / condition / so that findnext will work as intended? a. (pos < arr.length) && (arrpos != val) b. (arrpos != val) && (pos < arr.length)

Explanation:

To determine the correct condition, we analyze the method's purpose: find the first occurrence of val after start. The loop should continue while two conditions hold: 1) pos is within the array bounds (so we don't get an out - of - bounds error), and 2) the current element at pos is not equal to val (so we keep looking).

Analyzing Option A:

The condition (pos < arr.length) && (arr[pos] != val) first checks if pos is within the array (to avoid accessing elements outside the array) and then checks if the element at pos is not equal to val. If both are true, we increment pos to keep searching. When either pos is out of bounds (so we stop and return arr.length) or we find an element equal to val (so we stop and return that pos), the loop exits. This matches the method's intended behavior.

Analyzing Option B:

The condition (arr[pos] != val) && (pos < arr.length) first checks the element at pos and then checks the bounds. If pos is out of bounds, checking arr[pos] first will cause an out - of - bounds exception. So this condition is incorrect as it can lead to a runtime error.

Answer:

A. \((\text{pos} < \text{arr.length}) \&\& (\text{arr}[\text{pos}] != \text{val})\)