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complete the following conversions. be sure to show your work. (you wil…

Question

complete the following conversions. be sure to show your work. (you will not get credit for the answer if you do not show your work.)
-50 °f to:
1.______°c
2.______k
373.15 k
3.______°c
4.______°f
5 °c to:
5.______°f
6.______k
95 °f to:
7.______°c
8.______k
253.15 k to:
9.______°c
10.______°f
20 °c to:
11.______°f
12.______k

Explanation:

Step1: Use the formula for converting Fahrenheit to Celsius

The formula is \(C=\frac{5}{9}(F - 32)\). For \(F=- 50\), we have \(C=\frac{5}{9}(-50 - 32)=\frac{5}{9}\times(-82)\approx - 45.6\)

Step2: Convert Celsius to Kelvin

The formula is \(K = C+273.15\). Using \(C=-45.6\), we get \(K=-45.6 + 273.15=227.55\)

Step3: Convert Kelvin to Celsius

The formula is \(C=K - 273.15\). For \(K = 373.15\), \(C=373.15-273.15 = 100\)

Step4: Convert Celsius to Fahrenheit

The formula is \(F=\frac{9}{5}C+32\). Using \(C = 100\), \(F=\frac{9}{5}\times100+32=180 + 32=212\)

Step5: Convert Celsius to Fahrenheit

Using \(C = 5\) in \(F=\frac{9}{5}C+32\), \(F=\frac{9}{5}\times5+32=9 + 32=41\)

Step6: Convert Celsius to Kelvin

Using \(C = 5\) in \(K = C+273.15\), \(K=5+273.15=278.15\)

Step7: Convert Fahrenheit to Celsius

Using \(F = 95\) in \(C=\frac{5}{9}(F - 32)\), \(C=\frac{5}{9}(95 - 32)=\frac{5}{9}\times63 = 35\)

Step8: Convert Celsius to Kelvin

Using \(C = 35\) in \(K = C+273.15\), \(K=35+273.15=308.15\)

Step9: Convert Kelvin to Celsius

Using \(K = 253.15\) in \(C=K - 273.15\), \(C=253.15-273.15=-20\)

Step10: Convert Celsius to Fahrenheit

Using \(C=-20\) in \(F=\frac{9}{5}C+32\), \(F=\frac{9}{5}\times(-20)+32=-36 + 32=-4\)

Step11: Convert Celsius to Fahrenheit

Using \(C = 20\) in \(F=\frac{9}{5}C+32\), \(F=\frac{9}{5}\times20+32=36+32 = 68\)

Step12: Convert Celsius to Kelvin

Using \(C = 20\) in \(K = C+273.15\), \(K=20+273.15=293.15\)

Answer:

  1. \(-45.6\)
  2. \(227.55\)
  3. \(100\)
  4. \(212\)
  5. \(41\)
  6. \(278.15\)
  7. \(35\)
  8. \(308.15\)
  9. \(-20\)
  10. \(-4\)
  11. \(68\)
  12. \(293.15\)