Question

compared to red light, green light should have
a a longer wavelength
b a lower frequency
c a higher energy

question 5 (1 point)
what type of light is the most dangerous?

Explanation:

• For the first question:
• The energy of a photon is given by \(E = h

u\) (where \(h\) is Planck's constant and \(
u\) is the frequency). Also, \(c=\lambda
u\) (where \(c\) is the speed of light and \(\lambda\) is the wavelength). Red light has a longer wavelength (\(\lambda_{red}>\lambda_{green}\)). From \(c = \lambda
u\), \(
u=\frac{c}{\lambda}\), so \(
u_{green}>
u_{red}\). Since \(E = h
u\), \(E_{green}>E_{red}\).

• For the second question (assuming common knowledge in the context of light - types):
• Ultraviolet (UV) light (especially UV - C) is very dangerous as it can cause DNA damage in living cells, skin cancer, and damage to the eyes. X - rays and gamma rays (which are also forms of electromagnetic radiation) are also extremely dangerous as they have very high energy and can penetrate tissues and cause ionization and severe damage to biological systems. But if we consider the options in the visible - light - related context (if the second question was part of a set where only visible - light - adjacent types were considered), UV light is a common answer for dangerous light in the non - ionizing to ionizing radiation transition.

Answer:

• First question: C. a higher energy
• Second question (assuming a common - knowledge answer in a basic science context where UV is considered among non - ionizing to ionizing radiation): Ultraviolet (UV) light (or if ionizing radiation is considered, gamma rays or X - rays. But without more context, UV is a common answer for "dangerous light" in a basic science - light - properties context)