Question

ch statement predicts the kinetic energy of a 20 kg ball rolling at a v
will be twice that of the 10 kg ball moving at the same velocity.
will be equal to that of the 10 kg ball moving at the same velocity
will be 400 times that of the 10 kg ball moving at the same veloci
ll be four times as large as the 10 kg ball moving at the same vel

Explanation:

Step1: Recall Kinetic Energy Formula

The formula for kinetic energy (KE) is $KE = \frac{1}{2}mv^2$, where $m$ is mass and $v$ is velocity.

Step2: Calculate KE for 20 kg Ball

Let the velocity be $v$. For $m_1 = 20\space kg$, $KE_1=\frac{1}{2}(20)v^2 = 10v^2$.

Step3: Calculate KE for 10 kg Ball

For $m_2 = 10\space kg$, $KE_2=\frac{1}{2}(10)v^2 = 5v^2$.

Step4: Compare KE Values

Find the ratio $\frac{KE_1}{KE_2}=\frac{10v^2}{5v^2}=2$. So $KE_1 = 2\times KE_2$.

Answer:

The statement "will be twice that of the 10 kg ball moving at the same velocity" is correct.