6. a car is driven 215 km west and then 85 km south. what is the distance traveled and displacement of the car?

7. a car travels north for 240 mi in 3 hours. what is the car’s velocity?

8. use one of newton’s laws for each scenario to explain what happens in each of the following situations:
a. explain why a skateboarder eventually always stops.
b. explain why objects with greater masses (like a bowling ball) take more force to accelerate them than objects with small masses (like a baseball.)
c. explain why when mrs. joyner shoots a shotgun, her husband has to stand behind her and hold her shoulder when she pulls the trigger.

9. a 15.5 kg box is pushed across the lunch table. the acceleration of the box is 24.2 m/s². what was the net force applied to the box?

10. a beach ball is rolling in a straight line toward you at a speed of 9 m/sec. its momentum is 3 kg·m/sec. what is the mass of the beach ball?

Question

6. a car is driven 215 km west and then 85 km south. what is the distance traveled and displacement of the car?

7. a car travels north for 240 mi in 3 hours. what is the car’s velocity?

8. use one of newton’s laws for each scenario to explain what happens in each of the following situations:
   a. explain why a skateboarder eventually always stops.
   b. explain why objects with greater masses (like a bowling ball) take more force to accelerate them than objects with small masses (like a baseball.)
   c. explain why when mrs. joyner shoots a shotgun, her husband has to stand behind her and hold her shoulder when she pulls the trigger.

9. a 15.5 kg box is pushed across the lunch table. the acceleration of the box is 24.2 m/s². what was the net force applied to the box?

10. a beach ball is rolling in a straight line toward you at a speed of 9 m/sec. its momentum is 3 kg·m/sec. what is the mass of the beach ball?

Accepted Answer

### Question 6
# Explanation:
## Step1: Calculate Distance Traveled
Distance is the sum of the two paths. So, $ d = 215\,\text{km} + 85\,\text{km} $.
$ d = 300\,\text{km} $

## Step2: Calculate Displacement
Displacement is the straight - line distance from the start to the end. Using the Pythagorean theorem ($ s=\sqrt{x^{2}+y^{2}} $), where $ x = 215\,\text{km} $ (west) and $ y = 85\,\text{km} $ (south).
$ s=\sqrt{(215)^{2}+(85)^{2}}=\sqrt{46225 + 7225}=\sqrt{53450}\approx231.2\,\text{km} $
The direction is southwest (since it's west and then south).

# Answer:
Distance traveled: $ 300\,\text{km} $; Displacement: approximately $ 231.2\,\text{km} $ southwest

### Question 7
# Explanation:
## Step1: Recall Velocity Formula
Velocity $ v=\frac{\text{displacement}}{\text{time}} $. The displacement is 240 mi north and time is 3 hours.

## Step2: Calculate Velocity
$ v=\frac{240\,\text{mi}}{3\,\text{h}} = 80\,\text{mi/h} $ north.

# Answer:
The car's velocity is $ 80\,\text{mi/h} $ north

### Question 8
#### Part (a)
# Brief Explanations:
A skateboarder stops because of Newton's first law (law of inertia) and the presence of an external force (friction). The skateboarder will continue in motion unless a net external force acts on them. Friction between the skateboard and the ground, and air resistance act as external forces to slow them down until they stop.
# Answer:
Newton's first law: Friction (external force) stops the skateboarder.

#### Part (b)
# Brief Explanations:
Newton's second law ($ F = ma $) states that force is directly proportional to mass for a given acceleration. So, for the same acceleration, a larger mass (like a bowling ball) requires a larger force to accelerate it compared to a smaller mass (like a baseball).
# Answer:
Newton's second law ($ F = ma $): Larger mass needs more force for same acceleration.

#### Part (c)
# Brief Explanations:
Newton's third law states that for every action, there is an equal and opposite reaction. When the shotgun is fired, the force of the expanding gases pushing the bullet forward (action) creates a backward force (reaction) on the shotgun. The husband holds her to counteract this recoil force.
# Answer:
Newton's third law: Recoil force (reaction) from firing, husband holds to counter it.

### Question 9
# Explanation:
## Step1: Recall Newton's Second Law
Newton's second law is $ F = ma $, where $ m = 15.5\,\text{kg} $ and $ a=24.2\,\text{m/s}^2 $.

## Step2: Calculate Net Force
$ F=15.5\,\text{kg}\times24.2\,\text{m/s}^2 = 375.1\,\text{N} $

# Answer:
The net force applied to the box is $ 375.1\,\text{N} $

### Question 10
# Explanation:
## Step1: Recall Momentum Formula
Momentum $ p = mv $, where $ p = 3\,\text{kg}\cdot\text{m/s} $ and $ v = 9\,\text{m/s} $. We need to find $ m $.

## Step2: Solve for Mass
Rearranging the formula $ m=\frac{p}{v} $.
$ m=\frac{3\,\text{kg}\cdot\text{m/s}}{9\,\text{m/s}}=\frac{1}{3}\approx0.33\,\text{kg} $

# Answer:
The mass of the beach ball is $ \frac{1}{3}\,\text{kg}\approx0.33\,\text{kg} $

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QUESTION IMAGE

Question

Explanation:

Question 6

Step1: Calculate Distance Traveled

Step2: Calculate Displacement

Step1: Recall Velocity Formula

Step2: Calculate Velocity

Answer:

Question 7