Question

a car applies a force of 36.8 newtons for a 668 - meter loop, what was the work done? (1 point)
705 j
24,600 j
18.2 j
0 j

Explanation:

Step1: Recall the work formula

Work \(W = F\times d\), where \(F\) is force and \(d\) is distance.

Step2: Substitute the given values

Given \(F = 36.8\space N\) and \(d=668\space m\). Then \(W=36.8\times668\).

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Answer:

24,600 J