Question

1. calculate the wavelength of an electron ($m = 9.11\times10^{-28}$ g) moving at $3.66\times10^{6}$ m/s. a) $1.99\times10^{-10}$ m

b) $5.03\times10^{-10}$ m
c) $1.81\times10^{-10}$ m
d) $5.52\times10^{-9}$ m
e) $2.76\times10^{-9}$ m

1. determine the velocity of a medicine ball ($m = 10.0$ kg) with a wavelength of $1.33\times10^{-35}$ m.

a) $8.81$ m/s
b) $12.3$ m/s
c) $2.21$ m/s

Explanation:

Step1: Convert the mass of the electron to kg

Given \(m = 9.11\times10^{-28}\text{ g}\). Since \(1\text{ kg}=10^{3}\text{ g}\), then \(m = 9.11\times 10^{-31}\text{ kg}\)

Step2: Use the de - Broglie wavelength formula \(\lambda=\frac{h}{mv}\)

where \(h = 6.626\times10^{-34}\text{ J}\cdot\text{s}\), \(m = 9.11\times 10^{-31}\text{ kg}\), \(v = 3.66\times 10^{6}\text{ m/s}\)

Substitute the values into the formula:

$$
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$$

Answer:

A. \(1.99\times 10^{-10}\text{ m}\)