Question

bobby was walking at a velocity of -1.0 m/s when he accelerated at a rate of -2.0 m/s^2. this process took 12 seconds. which formula can be used to calculate bobbys final velocity (a)/(t) - vi = vf (a)/(t) * vi = vf (a)(t) + vi = vf (a)- (t) - vi = vf/s

Explanation:

Step1: Recall the kinematic formula

The kinematic formula for final velocity \(v_f\) is \(v_f=v_i + at\), where \(v_i\) is the initial velocity, \(a\) is the acceleration and \(t\) is the time.

Step2: Analyze the given options

• For the option \((a)/(t)-Vi = Vf\), from \(v_f = v_i+at\), we cannot get this form.
• For the option \((a)/(t)*Vi = Vf\), from \(v_f = v_i+at\), we cannot get this form.
• For the option \((a)(t)+Vi = Vf\), this is exactly the kinematic formula \(v_f=v_i + at\) (where \(a\) is acceleration, \(t\) is time and \(v_i\) is initial velocity)
• For the option \((a)-(t)-Vi = Vf/s\), from \(v_f = v_i+at\), we cannot get this form.

Answer:

\((a)(t)+Vi = Vf\)