Question

blue light waves have more energy than red light waves. which of these situations most likely produces a photoelectric effect? you may assume that the same metal is used in each situation. check all that apply: shining dim red light on a strip of metal shining bright red light on a strip of metal shining dim blue light on a strip of metal shining bright blue light on a strip of metal

Explanation:

The photoelectric effect occurs when photons have enough energy to eject electrons from a metal. The energy of a photon is related to its frequency (\(E = h
u\), where \(h\) is Planck's constant). Blue light has a higher frequency (and thus more energy per photon) than red light. The intensity (brightness) of the light affects the number of electrons ejected (more intense light means more photons, so more electrons if the energy per photon is sufficient), but not whether the effect occurs. For red light (low - energy photons), even bright red light doesn't have enough energy per photon to cause the photoelectric effect. For blue light (high - energy photons), both dim and bright blue light have photons with enough energy to cause the photoelectric effect.

Answer:

shining dim blue light on a strip of metal, shining bright blue light on a strip of metal