Question

a blue car weighing 1,302 kg is accelerating forward at a rate of 4 \frac{m}{s^{2}}. what is the forward force of the car? (1 point) 325.5 n 5,208 n 1,298 n 1,306 n

Explanation:

Step1: Recall Newton's second law

Newton's second law is \(F = ma\), where \(F\) is force, \(m\) is mass, and \(a\) is acceleration.

Step2: Substitute the given values

Given \(m = 1302\space kg\) and \(a=4\space m/s^{2}\). Substitute into \(F = ma\): \(F=(1302)(4)\).

Step3: Calculate the force

\(F = 1302\times4=5208\space N\)

Answer:

5,208 N