Question

in a 6 - bit johnson counter sequence there are a total of how many states, or bit patterns? 24 6 2 12

Explanation:

Step1: Recall Johnson counter formula

The number of states $N$ in an $n$-bit Johnson counter is given by $N = 2n$.

Step2: Substitute $n = 6$

Here $n = 6$, so $N=2\times6$.
$N = 12$.

Answer:

12