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balance the reaction, do not leave any fractions, dont leave anything b…

Question

balance the reaction, do not leave any fractions, dont leave anything blank, then answer the questions about the reaction
1 mo₂o₃ → 2 mo + 3 o₂
this is an 4 reaction.
is this a redox reaction? (yes/no)5, because mo⁺³ is reduced to mo⁰, and because o₂⁻² is 6 to o₂⁰.
will the reaction happen as it is written? (yes/no)7, because o₂ is very reactive and thus will not form. the reverse reaction would happen.
a. 1 b. 2 c. 3 d. 4 e. 5 f. 6 g. 7 h. 8
i. 9 j. 10 k. 12 l. 14 m. 16 n. 18 o. 20 p. 21
q. 24 r. 26 s. 28 t. synthesis u. decomposition
v. single displacement w. double displacement x. neutralization
y. combustion z. yes aa. no bb. reactive cc. stable
dd. oxidized ee. reduced

Explanation:

Step1: Balance the chemical equation

For the reaction \(Mo_2O_3
ightarrow Mo + O_2\), we use the method of balancing atoms.
The number of \(Mo\) atoms: on the left - hand side, there are \(2\) \(Mo\) atoms in \(Mo_2O_3\). On the right - hand side, let the coefficient of \(Mo\) be \(x\).
The number of \(O\) atoms: on the left - hand side, there are \(3\) \(O\) atoms in \(Mo_2O_3\). On the right - hand side, let the coefficient of \(O_2\) be \(y\).
We want to find integers \(a\), \(b\), and \(c\) such that \(aMo_2O_3 = bMo + cO_2\).
Balancing \(Mo\) atoms: \(2a=b\). Balancing \(O\) atoms: \(3a = 2c\). Let \(a = 2\), then \(b=4\) and \(c = 3\). So the balanced equation is \(2Mo_2O_3
ightarrow4Mo + 3O_2\)

Step2: Determine the type of reaction

The reaction \(2Mo_2O_3
ightarrow4Mo + 3O_2\) is a decomposition reaction (\(U\)) because a single compound (\(Mo_2O_3\)) breaks down into two or more simpler substances (\(Mo\) and \(O_2\))

Step3: Check if it is a redox reaction

In \(Mo_2O_3\), the oxidation state of \(Mo\) is \(+ 3\) (\(2x+3\times(-2)=0\), \(x = + 3\)) and in \(Mo\) it is \(0\). The oxidation state of \(O\) in \(Mo_2O_3\) is \(-2\) and in \(O_2\) it is \(0\). Since there is a change in oxidation states ( \(Mo\) is reduced and \(O\) is oxidized), it is a redox reaction (\(Z\)). \(O\) in \(O^{2 -}\) is oxidized (\(DD\)) to \(O_2\) (oxidation state \(0\))

Step4: Determine if the reaction occurs as written

The reaction \(2Mo_2O_3
ightarrow4Mo + 3O_2\) will not happen as written (\(AA\)) because \(O_2\) is very reactive and the reverse reaction (synthesis of \(Mo_2O_3\) from \(Mo\) and \(O_2\)) is more favorable

Answer:

  1. \(2\) (B)
  2. \(4\) (D)
  3. \(3\) (C)
  4. \(U\) (decomposition)
  5. \(Z\) (yes)
  6. \(DD\) (oxidized)
  7. \(AA\) (no)