QUESTION IMAGE
Question
balance the reaction, do not leave any fractions, dont leave anything blank, then answer the questions about the reaction
1 mo₂o₃ → 2 mo + 3 o₂
this is an 4 reaction.
is this a redox reaction? (yes/no)5, because mo⁺³ is reduced to mo⁰, and because o₂⁻² is 6 to o₂⁰.
will the reaction happen as it is written? (yes/no)7, because o₂ is very reactive and thus will not form. the reverse reaction would happen.
a. 1 b. 2 c. 3 d. 4 e. 5 f. 6 g. 7 h. 8
i. 9 j. 10 k. 12 l. 14 m. 16 n. 18 o. 20 p. 21
q. 24 r. 26 s. 28 t. synthesis u. decomposition
v. single displacement w. double displacement x. neutralization
y. combustion z. yes aa. no bb. reactive cc. stable
dd. oxidized ee. reduced
Step1: Balance the chemical equation
For the reaction \(Mo_2O_3
ightarrow Mo + O_2\), we use the method of balancing atoms.
The number of \(Mo\) atoms: on the left - hand side, there are \(2\) \(Mo\) atoms in \(Mo_2O_3\). On the right - hand side, let the coefficient of \(Mo\) be \(x\).
The number of \(O\) atoms: on the left - hand side, there are \(3\) \(O\) atoms in \(Mo_2O_3\). On the right - hand side, let the coefficient of \(O_2\) be \(y\).
We want to find integers \(a\), \(b\), and \(c\) such that \(aMo_2O_3 = bMo + cO_2\).
Balancing \(Mo\) atoms: \(2a=b\). Balancing \(O\) atoms: \(3a = 2c\). Let \(a = 2\), then \(b=4\) and \(c = 3\). So the balanced equation is \(2Mo_2O_3
ightarrow4Mo + 3O_2\)
Step2: Determine the type of reaction
The reaction \(2Mo_2O_3
ightarrow4Mo + 3O_2\) is a decomposition reaction (\(U\)) because a single compound (\(Mo_2O_3\)) breaks down into two or more simpler substances (\(Mo\) and \(O_2\))
Step3: Check if it is a redox reaction
In \(Mo_2O_3\), the oxidation state of \(Mo\) is \(+ 3\) (\(2x+3\times(-2)=0\), \(x = + 3\)) and in \(Mo\) it is \(0\). The oxidation state of \(O\) in \(Mo_2O_3\) is \(-2\) and in \(O_2\) it is \(0\). Since there is a change in oxidation states ( \(Mo\) is reduced and \(O\) is oxidized), it is a redox reaction (\(Z\)). \(O\) in \(O^{2 -}\) is oxidized (\(DD\)) to \(O_2\) (oxidation state \(0\))
Step4: Determine if the reaction occurs as written
The reaction \(2Mo_2O_3
ightarrow4Mo + 3O_2\) will not happen as written (\(AA\)) because \(O_2\) is very reactive and the reverse reaction (synthesis of \(Mo_2O_3\) from \(Mo\) and \(O_2\)) is more favorable
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
- \(2\) (B)
- \(4\) (D)
- \(3\) (C)
- \(U\) (decomposition)
- \(Z\) (yes)
- \(DD\) (oxidized)
- \(AA\) (no)