Question

1. an apple in a tree has a gravitational potential energy of 175 j and a mass of 0.36 g. how high from the ground is the apple?

Explanation:

Step1: Convert mass unit

The mass \(m = 0.36\space g=0.36\times10^{- 3}\space kg\).

Step2: Use gravitational - potential - energy formula

The formula for gravitational potential energy is \(U = mgh\), where \(U\) is gravitational potential energy, \(m\) is mass, \(g = 9.8\space m/s^{2}\) (acceleration due to gravity), and \(h\) is height.
We need to solve for \(h\), so \(h=\frac{U}{mg}\).
Substitute \(U = 175\space J\), \(m = 0.36\times10^{-3}\space kg\), and \(g = 9.8\space m/s^{2}\) into the formula:
\(h=\frac{175}{0.36\times10^{-3}\times9.8}\)
First, calculate \(0.36\times10^{-3}\times9.8=3.528\times10^{-3}\)
Then \(h=\frac{175}{3.528\times10^{-3}}\approx49603.17\space m\)

Answer:

The height of the apple from the ground is approximately \(49603.17\space m\)