Question

the ammeter in the circuit picture reads 6 ma. what is the voltage of the battery? 3.000 v 1.7 v 6 v 1.5 v 9 v 12 v 120 v

Explanation:

Step1: Convertir la corriente a amperios

$$I = 6\ mA=6\times10^{-3}\ A$$

Step2: Convertir la resistencia a ohmios

$$R = 20\ k\Omega=20\times10^{3}\ \Omega$$

Step3: Aplicar la ley de Ohm

$$V = I\times R$$
$$V=(6\times10^{-3}\ A)\times(20\times10^{3}\ \Omega)$$
$$V = 120\ V$$

Answer:

120 V