Question

adding a resistor in series with a load will cause:
select one:
a. a drop in voltage across the resistor.
b. a rise in voltage across the resistor.
c. no change in voltage to the load.
d. the fuse to blow.

Explanation:

Step1: Recall Ohm's Law

Ohm's Law is \(V = IR\). In a series circuit, the current \(I\) is the same throughout. When a resistor \(R\) is added in series, according to \(V = IR\), there will be a voltage drop \(V\) across that resistor.

Step2: Analyze other options

• Option b: A rise in voltage across the resistor is incorrect as per Ohm's Law application in series.
• Option c: In a series circuit, adding a resistor changes the total resistance. By \(V = IR\) (where \(V\) is the source voltage, \(I=\frac{V}{R_{total}}\) and \(R_{total}\) increases), the current \(I\) changes. For the load (which has its own resistance \(R_{load}\)), \(V_{load}=IR_{load}\), so the voltage to the load changes.
• Option d: There is no information suggesting the current will exceed the fuse - rating just by adding a resistor in series (it depends on resistor values and source voltage).

Answer:

A. a drop in voltage across the resistor.