QUESTION IMAGE
Question
a 3.98 kg block slides down a ramp with an angle of inclination of \\(42.1^{\circ}\\). if the block slides down with an acceleration of \\(1.43\text{ m/s}^2\\), what is the coefficient of kinetic friction?
\\(\bigcirc\\) 0.707
\\(\bigcirc\\) 0.457
\\(\bigcirc\\) 0.891
\\(\bigcirc\\) 0.610
Identify given values and target unknown
We are given:
- Mass of the block, \(m = 3.98\text{ kg}\)
- Angle of inclination, \(\theta = 42.1^\circ\)
- Acceleration down the ramp, \(a = 1.43\text{ m/s}^2\)
- Acceleration due to gravity, \(g = 9.80\text{ m/s}^2\)
We need to find the coefficient of kinetic friction, \(\mu_k\).
Resolve forces perpendicular to the incline
Using the Vector Resolution and Normal Force Calculation knowledge points
Set up the equation of motion down the incline
Using the Newtons Second Law knowledge point
Solve for the coefficient of kinetic friction
We can simplify the equation by dividing all terms by \(m\):
Calculate the numerical value of the coefficient
Substituting the values:
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- (A) 0.707 (Correct answer)
- (B) 0.457
- (C) 0.891
- (D) 0.610