QUESTION IMAGE
Question
a 3.98 kg block slides down a ramp with an angle of inclination of \\(42.1^{\circ}\\). if the block slides down with an acceleration of \\(1.43\text{ m/s}^2\\), what is the coefficient of kinetic friction?
\\(\bigcirc\\) 0.707
\\(\bigcirc\\) 0.457
\\(\bigcirc\\) 0.891
\\(\bigcirc\\) 0.610
Identify given values and target variable
We are given:
- Mass of the block, \(m = 3.98\text{ kg}\)
- Angle of inclination, \(\theta = 42.1^\circ\)
- Acceleration down the ramp, \(a = 1.43\text{ m/s}^2\)
- Acceleration due to gravity, \(g \approx 9.80\text{ m/s}^2\)
We need to find the coefficient of kinetic friction, \(\mu_k\).
Resolve forces perpendicular to the ramp
Using the Vector Resolution and Normal Force Calculation knowledge points
Set up the equation of motion along the ramp
Using the Newtons Second Law knowledge point
Solve for the coefficient of kinetic friction
We can simplify the equation by dividing all terms by mass \(m\):
Calculate the numerical value of the coefficient
Substitute the known values into the simplified formula:
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- (A) 0.707 (Correct answer)
- (B) 0.457
- (C) 0.891
- (D) 0.610